In a transverse progressive wave of amplitude A, the maximum particle velocity is four times its wave velocity. The wavelength of the wave is -
A
B
C
π π A
D
2 π π A
Text Solution
Verified by ExpertsThe correct answer is:
B
Here: Amplitude of the wave 
A Maximum velocity 
(where 
is velocity of wave) Maximum velocity relation is given by as 
or 
?(i)
Hence, wavelength of the wave 
[from eq. (i)]
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